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1213452342035 = 5501474839581
BaseRepresentation
bin10001101010000111011…
…001010101001100010011
311022000010120122220001122
4101222013121111030103
5124340122244421120
62325241410552455
7153445323503063
oct21520731251423
94260116586048
101213452342035
1142869323783a
1217721289872b
138a5745c63cb
1442a34da13a3
1521870bdea25
hex11a87655313

1213452342035 has 8 divisors (see below), whose sum is σ = 1456172148816. Its totient is φ = 970742314720.

The previous prime is 1213452342019. The next prime is 1213452342043. The reversal of 1213452342035 is 5302432543121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1213452342035 - 24 = 1213452342019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213452341986 and 1213452342004.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2169056 + ... + 2670525.

It is an arithmetic number, because the mean of its divisors is an integer number (182021518602).

Almost surely, 21213452342035 is an apocalyptic number.

1213452342035 is a deficient number, since it is larger than the sum of its proper divisors (242719806781).

1213452342035 is an equidigital number, since it uses as much as digits as its factorization.

1213452342035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4889733.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 1213452342035 its reverse (5302432543121), we get a palindrome (6515884885156).

The spelling of 1213452342035 in words is "one trillion, two hundred thirteen billion, four hundred fifty-two million, three hundred forty-two thousand, thirty-five".

Divisors: 1 5 50147 250735 4839581 24197905 242690468407 1213452342035