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121347527341 is a prime number
BaseRepresentation
bin111000100000011100…
…0000101001010101101
3102121012220210002111111
41301000320011022231
53442004431333331
6131425110352021
711524050651355
oct1610070051255
9377186702444
10121347527341
1147510574387
121b62705b611
13b59b423121
145c322b9b65
153253432db1
hex1c40e052ad

121347527341 has 2 divisors, whose sum is σ = 121347527342. Its totient is φ = 121347527340.

The previous prime is 121347527333. The next prime is 121347527423. The reversal of 121347527341 is 143725743121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109822646025 + 11524881316 = 331395^2 + 107354^2 .

It is a cyclic number.

It is not a de Polignac number, because 121347527341 - 23 = 121347527333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121347527294 and 121347527303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121347527141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60673763670 + 60673763671.

It is an arithmetic number, because the mean of its divisors is an integer number (60673763671).

Almost surely, 2121347527341 is an apocalyptic number.

It is an amenable number.

121347527341 is a deficient number, since it is larger than the sum of its proper divisors (1).

121347527341 is an equidigital number, since it uses as much as digits as its factorization.

121347527341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 141120, while the sum is 40.

The spelling of 121347527341 in words is "one hundred twenty-one billion, three hundred forty-seven million, five hundred twenty-seven thousand, three hundred forty-one".