Base | Representation |
---|---|
bin | 1011000010010110100110… |
… | …0111011011000111010011 |
3 | 1120222002200211001021101111 |
4 | 2300211221213123013103 |
5 | 3042310042431203210 |
6 | 41450433405514151 |
7 | 2361504651535423 |
oct | 260455147330723 |
9 | 46862624037344 |
10 | 12135054553555 |
11 | 39594a1a3191a |
12 | 143ba31272957 |
13 | 6a043b813bbb |
14 | 2dd4a84aa483 |
15 | 1609d98b488a |
hex | b09699db1d3 |
12135054553555 has 16 divisors (see below), whose sum is σ = 14667050613600. Its totient is φ = 9638055659520.
The previous prime is 12135054553553. The next prime is 12135054553561. The reversal of 12135054553555 is 55535545053121.
It is not a de Polignac number, because 12135054553555 - 21 = 12135054553553 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12135054553499 and 12135054553508.
It is not an unprimeable number, because it can be changed into a prime (12135054553553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 89115061 + ... + 89251129.
It is an arithmetic number, because the mean of its divisors is an integer number (916690663350).
Almost surely, 212135054553555 is an apocalyptic number.
12135054553555 is a deficient number, since it is larger than the sum of its proper divisors (2531996060045).
12135054553555 is a wasteful number, since it uses less digits than its factorization.
12135054553555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 264534.
The product of its (nonzero) digits is 5625000, while the sum is 49.
The spelling of 12135054553555 in words is "twelve trillion, one hundred thirty-five billion, fifty-four million, five hundred fifty-three thousand, five hundred fifty-five".
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