Base | Representation |
---|---|
bin | 1011000010010110100110… |
… | …0111011011001110110011 |
3 | 1120222002200211001022001021 |
4 | 2300211221213123032303 |
5 | 3042310042431212120 |
6 | 41450433405520311 |
7 | 2361504651540010 |
oct | 260455147331663 |
9 | 46862624038037 |
10 | 12135054554035 |
11 | 39594a1a32216 |
12 | 143ba31273097 |
13 | 6a043b81419a |
14 | 2dd4a84aa707 |
15 | 1609d98b4aaa |
hex | b09699db3b3 |
12135054554035 has 8 divisors (see below), whose sum is σ = 16642360531296. Its totient is φ = 8321180265600.
The previous prime is 12135054554033. The next prime is 12135054554047. The reversal of 12135054554035 is 53045545053121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12135054554035 - 21 = 12135054554033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12135054553982 and 12135054554000.
It is not an unprimeable number, because it can be changed into a prime (12135054554033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 173357922166 + ... + 173357922235.
It is an arithmetic number, because the mean of its divisors is an integer number (2080295066412).
Almost surely, 212135054554035 is an apocalyptic number.
12135054554035 is a deficient number, since it is larger than the sum of its proper divisors (4507305977261).
12135054554035 is an equidigital number, since it uses as much as digits as its factorization.
12135054554035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 346715844413.
The product of its (nonzero) digits is 900000, while the sum is 43.
The spelling of 12135054554035 in words is "twelve trillion, one hundred thirty-five billion, fifty-four million, five hundred fifty-four thousand, thirty-five".
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