Base | Representation |
---|---|
bin | 1011000010010110100110… |
… | …1101000100101100110011 |
3 | 1120222002200220211112000102 |
4 | 2300211221231010230303 |
5 | 3042310043321101421 |
6 | 41450433501343015 |
7 | 2361505000244366 |
oct | 260455155045463 |
9 | 46862626745012 |
10 | 12135056034611 |
11 | 39594a2853634 |
12 | 143ba31867a6b |
13 | 6a043bc12073 |
14 | 2dd4a87740dd |
15 | 1609d9aa860b |
hex | b0969b44b33 |
12135056034611 has 2 divisors, whose sum is σ = 12135056034612. Its totient is φ = 12135056034610.
The previous prime is 12135056034599. The next prime is 12135056034613. The reversal of 12135056034611 is 11643065053121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12135056034611 - 218 = 12135055772467 is a prime.
Together with 12135056034613, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12135056034613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067528017305 + 6067528017306.
It is an arithmetic number, because the mean of its divisors is an integer number (6067528017306).
Almost surely, 212135056034611 is an apocalyptic number.
12135056034611 is a deficient number, since it is larger than the sum of its proper divisors (1).
12135056034611 is an equidigital number, since it uses as much as digits as its factorization.
12135056034611 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 38.
The spelling of 12135056034611 in words is "twelve trillion, one hundred thirty-five billion, fifty-six million, thirty-four thousand, six hundred eleven".
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