Base | Representation |
---|---|
bin | 1011000010011011101101… |
… | …0011011100111111111111 |
3 | 1120222020020022212201020012 |
4 | 2300212323103130333333 |
5 | 3042320344303100421 |
6 | 41451221404213435 |
7 | 2361553632551255 |
oct | 260467323347777 |
9 | 46866208781205 |
10 | 12136425050111 |
11 | 395a0355aa1aa |
12 | 144015423a27b |
13 | 6a05c97326cb |
14 | 2dd5984dc5d5 |
15 | 160a69d7c95b |
hex | b09bb4dcfff |
12136425050111 has 2 divisors, whose sum is σ = 12136425050112. Its totient is φ = 12136425050110.
The previous prime is 12136425050093. The next prime is 12136425050171. The reversal of 12136425050111 is 11105052463121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12136425050111 - 210 = 12136425049087 is a prime.
It is a super-2 number, since 2×121364250501112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12136425050171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6068212525055 + 6068212525056.
It is an arithmetic number, because the mean of its divisors is an integer number (6068212525056).
Almost surely, 212136425050111 is an apocalyptic number.
12136425050111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12136425050111 is an equidigital number, since it uses as much as digits as its factorization.
12136425050111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 32.
The spelling of 12136425050111 in words is "twelve trillion, one hundred thirty-six billion, four hundred twenty-five million, fifty thousand, one hundred eleven".
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