Base | Representation |
---|---|
bin | 111000100001100010… |
… | …1111011001110000011 |
3 | 102121022111202012221122 |
4 | 1301003011323032003 |
5 | 3442043441223133 |
6 | 131432515342455 |
7 | 11525012006561 |
oct | 1610305731603 |
9 | 377274665848 |
10 | 121384711043 |
11 | 4752a561012 |
12 | 1b6375b1a2b |
13 | b5a6041b0b |
14 | 5c371d8a31 |
15 | 325682a498 |
hex | 1c4317b383 |
121384711043 has 2 divisors, whose sum is σ = 121384711044. Its totient is φ = 121384711042.
The previous prime is 121384711031. The next prime is 121384711081. The reversal of 121384711043 is 340117483121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121384711043 - 24 = 121384711027 is a prime.
It is a super-2 number, since 2×1213847110432 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121384710994 and 121384711012.
It is not a weakly prime, because it can be changed into another prime (121384711003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60692355521 + 60692355522.
It is an arithmetic number, because the mean of its divisors is an integer number (60692355522).
Almost surely, 2121384711043 is an apocalyptic number.
121384711043 is a deficient number, since it is larger than the sum of its proper divisors (1).
121384711043 is an equidigital number, since it uses as much as digits as its factorization.
121384711043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 121384711043 in words is "one hundred twenty-one billion, three hundred eighty-four million, seven hundred eleven thousand, forty-three".
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