Base | Representation |
---|---|
bin | 10110100111000100… |
… | …01101010110110111 |
3 | 1011022222110202011101 |
4 | 23103202031112313 |
5 | 144330024113100 |
6 | 5324310350531 |
7 | 606545621530 |
oct | 132342152667 |
9 | 34288422141 |
10 | 12138894775 |
11 | 516a0a9347 |
12 | 242935b447 |
13 | 11b5b75a97 |
14 | 832255687 |
15 | 4b0a5986a |
hex | 2d388d5b7 |
12138894775 has 48 divisors (see below), whose sum is σ = 17548751808. Its totient is φ = 8157312000.
The previous prime is 12138894773. The next prime is 12138894809. The reversal of 12138894775 is 57749883121.
It is not a de Polignac number, because 12138894775 - 21 = 12138894773 is a prime.
It is a super-3 number, since 3×121388947753 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12138894773) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3125835 + ... + 3129715.
It is an arithmetic number, because the mean of its divisors is an integer number (365598996).
Almost surely, 212138894775 is an apocalyptic number.
12138894775 is a deficient number, since it is larger than the sum of its proper divisors (5409857033).
12138894775 is a wasteful number, since it uses less digits than its factorization.
12138894775 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4252 (or 4247 counting only the distinct ones).
The product of its digits is 3386880, while the sum is 55.
It can be divided in two parts, 1213 and 8894775, that added together give a palindrome (8895988).
The spelling of 12138894775 in words is "twelve billion, one hundred thirty-eight million, eight hundred ninety-four thousand, seven hundred seventy-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •