Base | Representation |
---|---|
bin | 10110100111000100… |
… | …11001100001011011 |
3 | 1011022222120021111212 |
4 | 23103202121201123 |
5 | 144330032211403 |
6 | 5324311413335 |
7 | 606546220022 |
oct | 132342314133 |
9 | 34288507455 |
10 | 12138944603 |
11 | 516a132825 |
12 | 242938424b |
13 | 11b5b92676 |
14 | 8322698b9 |
15 | 4b0a694d8 |
hex | 2d389985b |
12138944603 has 2 divisors, whose sum is σ = 12138944604. Its totient is φ = 12138944602.
The previous prime is 12138944533. The next prime is 12138944647. The reversal of 12138944603 is 30644983121.
12138944603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (30644983121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12138944603 - 218 = 12138682459 is a prime.
It is not a weakly prime, because it can be changed into another prime (12138944663) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6069472301 + 6069472302.
It is an arithmetic number, because the mean of its divisors is an integer number (6069472302).
Almost surely, 212138944603 is an apocalyptic number.
12138944603 is a deficient number, since it is larger than the sum of its proper divisors (1).
12138944603 is an equidigital number, since it uses as much as digits as its factorization.
12138944603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 41.
The spelling of 12138944603 in words is "twelve billion, one hundred thirty-eight million, nine hundred forty-four thousand, six hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •