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121400111333 = 711709860723
BaseRepresentation
bin111000100010000000…
…0101011000011100101
3102121100120201122011202
41301010000223003211
53442111412030313
6131434225412245
711525256630434
oct1610400530345
9377316648152
10121400111333
114753821a526
121b64079a085
13b5a92a4707
145c3928711b
153257d6d558
hex1c4402b0e5

121400111333 has 4 divisors (see below), whose sum is σ = 123109972128. Its totient is φ = 119690250540.

The previous prime is 121400111311. The next prime is 121400111341. The reversal of 121400111333 is 333111004121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121400111333 - 224 = 121383334117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121400111383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 854930291 + ... + 854930432.

It is an arithmetic number, because the mean of its divisors is an integer number (30777493032).

Almost surely, 2121400111333 is an apocalyptic number.

It is an amenable number.

121400111333 is a deficient number, since it is larger than the sum of its proper divisors (1709860795).

121400111333 is an equidigital number, since it uses as much as digits as its factorization.

121400111333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1709860794.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 121400111333 its reverse (333111004121), we get a palindrome (454511115454).

The spelling of 121400111333 in words is "one hundred twenty-one billion, four hundred million, one hundred eleven thousand, three hundred thirty-three".

Divisors: 1 71 1709860723 121400111333