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12140121314161 is a prime number
BaseRepresentation
bin1011000010101001011110…
…0111100101001101110001
31120222120202221001101021201
42300222113213211031301
53042400432024023121
641453032244051201
72362044344355301
oct260522747451561
946876687041251
1012140121314161
113960661a98085
121440a06093b01
136a0a684489b9
142dd829389601
15160bd4606e91
hexb0a979e5371

12140121314161 has 2 divisors, whose sum is σ = 12140121314162. Its totient is φ = 12140121314160.

The previous prime is 12140121314047. The next prime is 12140121314177. The reversal of 12140121314161 is 16141312104121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8526487600225 + 3613633713936 = 2920015^2 + 1900956^2 .

It is a cyclic number.

It is not a de Polignac number, because 12140121314161 - 225 = 12140087759729 is a prime.

It is not a weakly prime, because it can be changed into another prime (12140121314861) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070060657080 + 6070060657081.

It is an arithmetic number, because the mean of its divisors is an integer number (6070060657081).

Almost surely, 212140121314161 is an apocalyptic number.

It is an amenable number.

12140121314161 is a deficient number, since it is larger than the sum of its proper divisors (1).

12140121314161 is an equidigital number, since it uses as much as digits as its factorization.

12140121314161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 28.

Adding to 12140121314161 its reverse (16141312104121), we get a palindrome (28281433418282).

The spelling of 12140121314161 in words is "twelve trillion, one hundred forty billion, one hundred twenty-one million, three hundred fourteen thousand, one hundred sixty-one".