121401304333 has 4 divisors (see below), whose sum is σ = 121409155708. Its totient is φ = 121393452960.

The previous prime is 121401304331. The next prime is 121401304361. The reversal of 121401304333 is 333403104121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 39337962244 + 82063342089 = 198338^2 + 286467^2 .

It is a cyclic number.

It is not a de Polignac number, because 121401304333 - 2¹ = 121401304331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121401304298 and 121401304307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121401304331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3902448 + ... + 3933433.

It is an arithmetic number, because the mean of its divisors is an integer number (30352288927).

Almost surely, 2^121401304333 is an apocalyptic number.

It is an amenable number.

121401304333 is a deficient number, since it is larger than the sum of its proper divisors (7851375).

121401304333 is an equidigital number, since it uses as much as digits as its factorization.

121401304333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7851374.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 121401304333 its reverse (333403104121), we get a palindrome (454804408454).

The spelling of 121401304333 in words is "one hundred twenty-one billion, four hundred one million, three hundred four thousand, three hundred thirty-three".