121401455531 has 2 divisors, whose sum is σ = 121401455532. Its totient is φ = 121401455530.

The previous prime is 121401455467. The next prime is 121401455533. The reversal of 121401455531 is 135554104121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121401455531 - 2⁶ = 121401455467 is a prime.

It is a super-3 number, since 3×121401455531³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

Together with 121401455533, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (121401455533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60700727765 + 60700727766.

It is an arithmetic number, because the mean of its divisors is an integer number (60700727766).

Almost surely, 2^121401455531 is an apocalyptic number.

121401455531 is a deficient number, since it is larger than the sum of its proper divisors (1).

121401455531 is an equidigital number, since it uses as much as digits as its factorization.

121401455531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 121401455531 its reverse (135554104121), we get a palindrome (256955559652).

The spelling of 121401455531 in words is "one hundred twenty-one billion, four hundred one million, four hundred fifty-five thousand, five hundred thirty-one".