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121402443301 = 196389602279
BaseRepresentation
bin111000100010000100…
…1100100011000100101
3102121100202010010000221
41301010021210120211
53442113011141201
6131434351404341
711525315512246
oct1610411443045
9377322103027
10121402443301
1147539572577
121b6415236b1
13b5a990cc89
145c396d2ccd
15325817e4a1
hex1c44264625

121402443301 has 4 divisors (see below), whose sum is σ = 127792045600. Its totient is φ = 115012841004.

The previous prime is 121402443287. The next prime is 121402443353. The reversal of 121402443301 is 103344204121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121402443301 - 213 = 121402435109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121402443361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3194801121 + ... + 3194801158.

It is an arithmetic number, because the mean of its divisors is an integer number (31948011400).

Almost surely, 2121402443301 is an apocalyptic number.

It is an amenable number.

121402443301 is a deficient number, since it is larger than the sum of its proper divisors (6389602299).

121402443301 is an equidigital number, since it uses as much as digits as its factorization.

121402443301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6389602298.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 121402443301 its reverse (103344204121), we get a palindrome (224746647422).

The spelling of 121402443301 in words is "one hundred twenty-one billion, four hundred two million, four hundred forty-three thousand, three hundred one".

Divisors: 1 19 6389602279 121402443301