121403114132443 has 16 divisors (see below), whose sum is σ = 142628919715296. Its totient is φ = 101875678467840.

The previous prime is 121403114132413. The next prime is 121403114132459. The reversal of 121403114132443 is 344231411304121.

It is a cyclic number.

It is not a de Polignac number, because 121403114132443 - 2⁵ = 121403114132411 is a prime.

It is a super-3 number, since 3×121403114132443³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121403114132399 and 121403114132408.

It is not an unprimeable number, because it can be changed into a prime (121403114132413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9516855 + ... + 18258607.

It is an arithmetic number, because the mean of its divisors is an integer number (8914307482206).

Almost surely, 2^{121403114132443} is an apocalyptic number.

121403114132443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

121403114132443 is a deficient number, since it is larger than the sum of its proper divisors (21225805582853).

121403114132443 is a wasteful number, since it uses less digits than its factorization.

121403114132443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8838894.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 121403114132443 its reverse (344231411304121), we get a palindrome (465634525436564).

The spelling of 121403114132443 in words is "one hundred twenty-one trillion, four hundred three billion, one hundred fourteen million, one hundred thirty-two thousand, four hundred forty-three".