12141024433 has 8 divisors (see below), whose sum is σ = 12239555328. Its totient is φ = 12042890784.

The previous prime is 12141024409. The next prime is 12141024457. The reversal of 12141024433 is 33442014121.

12141024433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (12141024409) and next prime (12141024457).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12141024433 - 2¹³ = 12141016241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12141024398 and 12141024407.

It is not an unprimeable number, because it can be changed into a prime (12141024473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37785 + ... + 160342.

It is an arithmetic number, because the mean of its divisors is an integer number (1529944416).

Almost surely, 2^12141024433 is an apocalyptic number.

It is an amenable number.

12141024433 is a deficient number, since it is larger than the sum of its proper divisors (98530895).

12141024433 is a wasteful number, since it uses less digits than its factorization.

12141024433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 198623.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12141024433 its reverse (33442014121), we get a palindrome (45583038554).

The spelling of 12141024433 in words is "twelve billion, one hundred forty-one million, twenty-four thousand, four hundred thirty-three".