1214113 has 2 divisors, whose sum is σ = 1214114. Its totient is φ = 1214112.

The previous prime is 1214093. The next prime is 1214117. The reversal of 1214113 is 3114121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 685584 + 528529 = 828^2 + 727^2 .

It is a cyclic number.

It is not a de Polignac number, because 1214113 - 2⁹ = 1213601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1214093 and 1214102.

It is not a weakly prime, because it can be changed into another prime (1214117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607056 + 607057.

It is an arithmetic number, because the mean of its divisors is an integer number (607057).

2^1214113 is an apocalyptic number.

It is an amenable number.

1214113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214113 is an equidigital number, since it uses as much as digits as its factorization.

1214113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24, while the sum is 13.

The square root of 1214113 is about 1101.8679594216. The cubic root of 1214113 is about 106.6808260283.

Adding to 1214113 its reverse (3114121), we get a palindrome (4328234).

The spelling of 1214113 in words is "one million, two hundred fourteen thousand, one hundred thirteen".