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1214121431123 is a prime number
BaseRepresentation
bin10001101010101111010…
…001101101000001010011
311022001212012200010201222
4101222233101231001103
5124343010041243443
62325432031515255
7153501026613116
oct21525721550123
94261765603658
101214121431123
114289a6994327
1217737a988b2b
138a650102003
1442a99bb057d
15218ae808468
hex11aaf46d053

1214121431123 has 2 divisors, whose sum is σ = 1214121431124. Its totient is φ = 1214121431122.

The previous prime is 1214121431077. The next prime is 1214121431147. The reversal of 1214121431123 is 3211341214121.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (3211341214121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1214121431123 - 218 = 1214121168979 is a prime.

It is a super-2 number, since 2×12141214311232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1214121431092 and 1214121431101.

It is not a weakly prime, because it can be changed into another prime (1214121431323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607060715561 + 607060715562.

It is an arithmetic number, because the mean of its divisors is an integer number (607060715562).

Almost surely, 21214121431123 is an apocalyptic number.

1214121431123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214121431123 is an equidigital number, since it uses as much as digits as its factorization.

1214121431123 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 26.

Adding to 1214121431123 its reverse (3211341214121), we get a palindrome (4425462645244).

The spelling of 1214121431123 in words is "one trillion, two hundred fourteen billion, one hundred twenty-one million, four hundred thirty-one thousand, one hundred twenty-three".