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1214122404041 is a prime number
BaseRepresentation
bin10001101010101111010…
…101011010100011001001
311022001212021111120022222
4101222233111122203021
5124343010313412131
62325432104423425
7153501041104451
oct21525725324311
94261767446288
101214122404041
114289a7499298
1217737b177b75
138a650382ac1
1442a99d84d61
15218ae94b87b
hex11aaf55a8c9

1214122404041 has 2 divisors, whose sum is σ = 1214122404042. Its totient is φ = 1214122404040.

The previous prime is 1214122404023. The next prime is 1214122404043. The reversal of 1214122404041 is 1404042214121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 857468592016 + 356653812025 = 925996^2 + 597205^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1214122404041 is a prime.

Together with 1214122404043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1214122404041.

It is not a weakly prime, because it can be changed into another prime (1214122404043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607061202020 + 607061202021.

It is an arithmetic number, because the mean of its divisors is an integer number (607061202021).

Almost surely, 21214122404041 is an apocalyptic number.

It is an amenable number.

1214122404041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214122404041 is an equidigital number, since it uses as much as digits as its factorization.

1214122404041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2048, while the sum is 26.

Adding to 1214122404041 its reverse (1404042214121), we get a palindrome (2618164618162).

The spelling of 1214122404041 in words is "one trillion, two hundred fourteen billion, one hundred twenty-two million, four hundred four thousand, forty-one".