Base | Representation |
---|---|
bin | 10110100111010110… |
… | …11011110000000011 |
3 | 1011100011000121101021 |
4 | 23103223123300003 |
5 | 144331134004102 |
6 | 5324434250311 |
7 | 606605313034 |
oct | 132353336003 |
9 | 34304017337 |
10 | 12141313027 |
11 | 51705001a8 |
12 | 242a126997 |
13 | 11b65116bc |
14 | 8326c4a8b |
15 | 4b0d86137 |
hex | 2d3adbc03 |
12141313027 has 2 divisors, whose sum is σ = 12141313028. Its totient is φ = 12141313026.
The previous prime is 12141313021. The next prime is 12141313033. The reversal of 12141313027 is 72031314121.
It is a balanced prime because it is at equal distance from previous prime (12141313021) and next prime (12141313033).
It is a cyclic number.
It is not a de Polignac number, because 12141313027 - 231 = 9993829379 is a prime.
It is a super-2 number, since 2×121413130272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12141312992 and 12141313010.
It is not a weakly prime, because it can be changed into another prime (12141313021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070656513 + 6070656514.
It is an arithmetic number, because the mean of its divisors is an integer number (6070656514).
Almost surely, 212141313027 is an apocalyptic number.
12141313027 is a deficient number, since it is larger than the sum of its proper divisors (1).
12141313027 is an equidigital number, since it uses as much as digits as its factorization.
12141313027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 12141313027 its reverse (72031314121), we get a palindrome (84172627148).
The spelling of 12141313027 in words is "twelve billion, one hundred forty-one million, three hundred thirteen thousand, twenty-seven".
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