12141411320133 has 24 divisors (see below), whose sum is σ = 17582747554008. Its totient is φ = 8073444068352.

The previous prime is 12141411320117. The next prime is 12141411320153. The reversal of 12141411320133 is 33102311414121.

12141411320133 is a `hidden beast` number, since 1 + 2 + 1 + 41 + 411 + 3 + 201 + 3 + 3 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 1469023993089 + 10672387327044 = 1212033^2 + 3266862^2 .

It is not a de Polignac number, because 12141411320133 - 2⁴ = 12141411320117 is a prime.

It is a super-2 number, since 2×12141411320133² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12141411320097 and 12141411320106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12141411320153) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14386641 + ... + 15207177.

It is an arithmetic number, because the mean of its divisors is an integer number (732614481417).

Almost surely, 2^{12141411320133} is an apocalyptic number.

It is an amenable number.

12141411320133 is a deficient number, since it is larger than the sum of its proper divisors (5441336233875).

12141411320133 is a wasteful number, since it uses less digits than its factorization.

12141411320133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 824773 (or 824770 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 12141411320133 its reverse (33102311414121), we get a palindrome (45243722734254).

The spelling of 12141411320133 in words is "twelve trillion, one hundred forty-one billion, four hundred eleven million, three hundred twenty thousand, one hundred thirty-three".