Base | Representation |
---|---|
bin | 111000100010011011… |
… | …0111100110111010101 |
3 | 102121101120111112022101 |
4 | 1301010312330313111 |
5 | 3442124032340203 |
6 | 131435454402101 |
7 | 11525521601536 |
oct | 1610466746725 |
9 | 377346445271 |
10 | 121414340053 |
11 | 475452587a6 |
12 | 1b645500331 |
13 | b5ac216c86 |
14 | 5c3b10c68d |
15 | 325922e41d |
hex | 1c44dbcdd5 |
121414340053 has 2 divisors, whose sum is σ = 121414340054. Its totient is φ = 121414340052.
The previous prime is 121414340039. The next prime is 121414340149. The reversal of 121414340053 is 350043414121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79790995729 + 41623344324 = 282473^2 + 204018^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121414340053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121414340953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60707170026 + 60707170027.
It is an arithmetic number, because the mean of its divisors is an integer number (60707170027).
Almost surely, 2121414340053 is an apocalyptic number.
It is an amenable number.
121414340053 is a deficient number, since it is larger than the sum of its proper divisors (1).
121414340053 is an equidigital number, since it uses as much as digits as its factorization.
121414340053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 121414340053 its reverse (350043414121), we get a palindrome (471457754174).
The spelling of 121414340053 in words is "one hundred twenty-one billion, four hundred fourteen million, three hundred forty thousand, fifty-three".
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