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121414514141 is a prime number
BaseRepresentation
bin111000100010011011…
…1100111010111011101
3102121101120211101010002
41301010313213113131
53442124103423031
6131435502224045
711525523225224
oct1610467472735
9377346741102
10121414514141
1147545367578
121b645585025
13b5ac27829b
145c3b155cbb
153259265ccb
hex1c44de75dd

121414514141 has 2 divisors, whose sum is σ = 121414514142. Its totient is φ = 121414514140.

The previous prime is 121414514129. The next prime is 121414514167. The reversal of 121414514141 is 141415414121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98331789241 + 23082724900 = 313579^2 + 151930^2 .

It is an emirp because it is prime and its reverse (141415414121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121414514141 - 210 = 121414513117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121414514101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60707257070 + 60707257071.

It is an arithmetic number, because the mean of its divisors is an integer number (60707257071).

Almost surely, 2121414514141 is an apocalyptic number.

It is an amenable number.

121414514141 is a deficient number, since it is larger than the sum of its proper divisors (1).

121414514141 is an equidigital number, since it uses as much as digits as its factorization.

121414514141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2560, while the sum is 29.

Adding to 121414514141 its reverse (141415414121), we get a palindrome (262829928262).

The spelling of 121414514141 in words is "one hundred twenty-one billion, four hundred fourteen million, five hundred fourteen thousand, one hundred forty-one".