Base | Representation |
---|---|
bin | 1011000010101111000001… |
… | …1011011100011110100111 |
3 | 1120222201121202201202021211 |
4 | 2300223300123130132213 |
5 | 3042412004443223441 |
6 | 41453440151452251 |
7 | 2362126306154446 |
oct | 260536033343647 |
9 | 46881552652254 |
10 | 12141611304871 |
11 | 3961257061164 |
12 | 1441161087087 |
13 | 6a0c450450c9 |
14 | 2dd92b204d5d |
15 | 160c70325a81 |
hex | b0af06dc7a7 |
12141611304871 has 2 divisors, whose sum is σ = 12141611304872. Its totient is φ = 12141611304870.
The previous prime is 12141611304853. The next prime is 12141611304913. The reversal of 12141611304871 is 17840311614121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12141611304871 - 27 = 12141611304743 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12141611302871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070805652435 + 6070805652436.
It is an arithmetic number, because the mean of its divisors is an integer number (6070805652436).
Almost surely, 212141611304871 is an apocalyptic number.
12141611304871 is a deficient number, since it is larger than the sum of its proper divisors (1).
12141611304871 is an equidigital number, since it uses as much as digits as its factorization.
12141611304871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 40.
Adding to 12141611304871 its reverse (17840311614121), we get a palindrome (29981922918992).
The spelling of 12141611304871 in words is "twelve trillion, one hundred forty-one billion, six hundred eleven million, three hundred four thousand, eight hundred seventy-one".
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