Base | Representation |
---|---|
bin | 1011000010110000011110… |
… | …1101111000010011101111 |
3 | 1120222202121222220210122221 |
4 | 2300230013231320103233 |
5 | 3042413310003412143 |
6 | 41453543030020211 |
7 | 2362142062140442 |
oct | 260540755702357 |
9 | 46882558823587 |
10 | 12142002013423 |
11 | 3961437660297 |
12 | 144124baa7667 |
13 | 6a0ca7c824b9 |
14 | 2dd96706b659 |
15 | 160c947a12ed |
hex | b0b07b784ef |
12142002013423 has 4 divisors (see below), whose sum is σ = 12470164230040. Its totient is φ = 11813839796808.
The previous prime is 12142002013403. The next prime is 12142002013459. The reversal of 12142002013423 is 32431020024121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12142002013423 - 221 = 12141999916271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12142002013403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164081108253 + ... + 164081108326.
It is an arithmetic number, because the mean of its divisors is an integer number (3117541057510).
Almost surely, 212142002013423 is an apocalyptic number.
12142002013423 is a deficient number, since it is larger than the sum of its proper divisors (328162216617).
12142002013423 is an equidigital number, since it uses as much as digits as its factorization.
12142002013423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 328162216616.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12142002013423 its reverse (32431020024121), we get a palindrome (44573022037544).
The spelling of 12142002013423 in words is "twelve trillion, one hundred forty-two billion, two million, thirteen thousand, four hundred twenty-three".
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