12142064454613 has 4 divisors (see below), whose sum is σ = 12781120478560. Its totient is φ = 11503008430668.

The previous prime is 12142064454601. The next prime is 12142064454643. The reversal of 12142064454613 is 31645446024121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12142064454613 - 2⁴¹ = 9943041199061 is a prime.

It is a super-3 number, since 3×12142064454613³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12142064454613.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12142064454643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 319528011945 + ... + 319528011982.

It is an arithmetic number, because the mean of its divisors is an integer number (3195280119640).

Almost surely, 2^{12142064454613} is an apocalyptic number.

It is an amenable number.

12142064454613 is a deficient number, since it is larger than the sum of its proper divisors (639056023947).

12142064454613 is an equidigital number, since it uses as much as digits as its factorization.

12142064454613 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 639056023946.

The product of its (nonzero) digits is 552960, while the sum is 43.

The spelling of 12142064454613 in words is "twelve trillion, one hundred forty-two billion, sixty-four million, four hundred fifty-four thousand, six hundred thirteen".