Base | Representation |
---|---|
bin | 10001101010110100100… |
… | …100111000000110000101 |
3 | 11022002002101222100022121 |
4 | 101222310210320012011 |
5 | 124343200321441201 |
6 | 2325444525325541 |
7 | 153503156425234 |
oct | 21526444700605 |
9 | 4262071870277 |
10 | 1214210343301 |
11 | 428a420a236a |
12 | 1773a47068b1 |
13 | 8a665662a77 |
14 | 42aa7916b1b |
15 | 218b751c9a1 |
hex | 11ab4938185 |
1214210343301 has 16 divisors (see below), whose sum is σ = 1243443052800. Its totient is φ = 1185335683840.
The previous prime is 1214210343257. The next prime is 1214210343347. The reversal of 1214210343301 is 1033430124121.
It is a cyclic number.
It is not a de Polignac number, because 1214210343301 - 219 = 1214209819013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1214210343361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8052600 + ... + 8201998.
It is an arithmetic number, because the mean of its divisors is an integer number (77715190800).
Almost surely, 21214210343301 is an apocalyptic number.
It is an amenable number.
1214210343301 is a deficient number, since it is larger than the sum of its proper divisors (29232709499).
1214210343301 is a wasteful number, since it uses less digits than its factorization.
1214210343301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150596.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1214210343301 its reverse (1033430124121), we get a palindrome (2247640467422).
The spelling of 1214210343301 in words is "one trillion, two hundred fourteen billion, two hundred ten million, three hundred forty-three thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •