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1214211103111 = 6119905100051
BaseRepresentation
bin10001101010110100100…
…111110001100110000111
311022002002110101221120201
4101222310213301212013
5124343201020244421
62325444553511331
7153503166041356
oct21526447614607
94262073357521
101214211103111
11428a42571206
121773a4a12547
138a66586a866
1442aa7a7399d
15218b761cb91
hex11ab49f1987

1214211103111 has 4 divisors (see below), whose sum is σ = 1234116203224. Its totient is φ = 1194306003000.

The previous prime is 1214211103081. The next prime is 1214211103117. The reversal of 1214211103111 is 1113011124121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1214211103111 - 211 = 1214211101063 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214211103117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9952549965 + ... + 9952550086.

It is an arithmetic number, because the mean of its divisors is an integer number (308529050806).

Almost surely, 21214211103111 is an apocalyptic number.

1214211103111 is a deficient number, since it is larger than the sum of its proper divisors (19905100113).

1214211103111 is an equidigital number, since it uses as much as digits as its factorization.

1214211103111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19905100112.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 1214211103111 its reverse (1113011124121), we get a palindrome (2327222227232).

The spelling of 1214211103111 in words is "one trillion, two hundred fourteen billion, two hundred eleven million, one hundred three thousand, one hundred eleven".

Divisors: 1 61 19905100051 1214211103111