Base | Representation |
---|---|
bin | 10001101010110100101… |
… | …111000011011011101001 |
3 | 11022002002120222212221211 |
4 | 101222310233003123221 |
5 | 124343202012324202 |
6 | 2325445102433121 |
7 | 153503221206265 |
oct | 21526457033351 |
9 | 4262076885854 |
10 | 1214213011177 |
11 | 428a43654821 |
12 | 1773a55927a1 |
13 | 8a6660881aa |
14 | 42aa800d0a5 |
15 | 218b78981d7 |
hex | 11ab4bc36e9 |
1214213011177 has 2 divisors, whose sum is σ = 1214213011178. Its totient is φ = 1214213011176.
The previous prime is 1214213011163. The next prime is 1214213011241. The reversal of 1214213011177 is 7711103124121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1213674585561 + 538425616 = 1101669^2 + 23204^2 .
It is an emirp because it is prime and its reverse (7711103124121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1214213011177 - 219 = 1214212486889 is a prime.
It is not a weakly prime, because it can be changed into another prime (1214213011147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607106505588 + 607106505589.
It is an arithmetic number, because the mean of its divisors is an integer number (607106505589).
Almost surely, 21214213011177 is an apocalyptic number.
It is an amenable number.
1214213011177 is a deficient number, since it is larger than the sum of its proper divisors (1).
1214213011177 is an equidigital number, since it uses as much as digits as its factorization.
1214213011177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2352, while the sum is 31.
Adding to 1214213011177 its reverse (7711103124121), we get a palindrome (8925316135298).
The spelling of 1214213011177 in words is "one trillion, two hundred fourteen billion, two hundred thirteen million, eleven thousand, one hundred seventy-seven".
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