Base | Representation |
---|---|
bin | 10001101010110100101… |
… | …111000011011100101001 |
3 | 11022002002120222220001012 |
4 | 101222310233003130221 |
5 | 124343202012324431 |
6 | 2325445102433305 |
7 | 153503221206416 |
oct | 21526457033451 |
9 | 4262076886035 |
10 | 1214213011241 |
11 | 428a4365487a |
12 | 1773a5592835 |
13 | 8a666088229 |
14 | 42aa800d10d |
15 | 218b789822b |
hex | 11ab4bc3729 |
1214213011241 has 2 divisors, whose sum is σ = 1214213011242. Its totient is φ = 1214213011240.
The previous prime is 1214213011177. The next prime is 1214213011267. The reversal of 1214213011241 is 1421103124121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 997961040400 + 216251970841 = 998980^2 + 465029^2 .
It is a cyclic number.
It is not a de Polignac number, because 1214213011241 - 26 = 1214213011177 is a prime.
It is not a weakly prime, because it can be changed into another prime (1214213011741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607106505620 + 607106505621.
It is an arithmetic number, because the mean of its divisors is an integer number (607106505621).
Almost surely, 21214213011241 is an apocalyptic number.
It is an amenable number.
1214213011241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1214213011241 is an equidigital number, since it uses as much as digits as its factorization.
1214213011241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1214213011241 its reverse (1421103124121), we get a palindrome (2635316135362).
The spelling of 1214213011241 in words is "one trillion, two hundred fourteen billion, two hundred thirteen million, eleven thousand, two hundred forty-one".
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