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1214213011741 is a prime number
BaseRepresentation
bin10001101010110100101…
…111000011100100011101
311022002002120222220201201
4101222310233003210131
5124343202012333431
62325445102435501
7153503221211032
oct21526457034435
94262076886651
101214213011741
11428a43655194
121773a5592b91
138a666088522
1442aa800d389
15218b7898461
hex11ab4bc391d

1214213011741 has 2 divisors, whose sum is σ = 1214213011742. Its totient is φ = 1214213011740.

The previous prime is 1214213011729. The next prime is 1214213011747. The reversal of 1214213011741 is 1471103124121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 937757887641 + 276455124100 = 968379^2 + 525790^2 .

It is an emirp because it is prime and its reverse (1471103124121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1214213011741 - 25 = 1214213011709 is a prime.

It is a super-2 number, since 2×12142130117412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1214213011747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607106505870 + 607106505871.

It is an arithmetic number, because the mean of its divisors is an integer number (607106505871).

Almost surely, 21214213011741 is an apocalyptic number.

It is an amenable number.

1214213011741 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214213011741 is an equidigital number, since it uses as much as digits as its factorization.

1214213011741 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 28.

Adding to 1214213011741 its reverse (1471103124121), we get a palindrome (2685316135862).

The spelling of 1214213011741 in words is "one trillion, two hundred fourteen billion, two hundred thirteen million, eleven thousand, seven hundred forty-one".