Base | Representation |
---|---|
bin | 1011000010110001000000… |
… | …1001011011000110011111 |
3 | 1120222202222212001121022010 |
4 | 2300230100021123012133 |
5 | 3042414102210422201 |
6 | 41454005041322303 |
7 | 2362145430300501 |
oct | 260542011330637 |
9 | 46882885047263 |
10 | 12142143451551 |
11 | 39614aa484903 |
12 | 144128b336393 |
13 | 6a0ccb3742b9 |
14 | 2dd97bb67d71 |
15 | 160ca1dddbd6 |
hex | b0b1025b19f |
12142143451551 has 8 divisors (see below), whose sum is σ = 16209195959680. Its totient is φ = 8084926622232.
The previous prime is 12142143451519. The next prime is 12142143451553. The reversal of 12142143451551 is 15515434124121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12142143451551 - 25 = 12142143451519 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12142143451553) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2458916821 + ... + 2458921758.
It is an arithmetic number, because the mean of its divisors is an integer number (2026149494960).
Almost surely, 212142143451551 is an apocalyptic number.
12142143451551 is a deficient number, since it is larger than the sum of its proper divisors (4067052508129).
12142143451551 is an equidigital number, since it uses as much as digits as its factorization.
12142143451551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4917839405.
The product of its digits is 96000, while the sum is 39.
Adding to 12142143451551 its reverse (15515434124121), we get a palindrome (27657577575672).
The spelling of 12142143451551 in words is "twelve trillion, one hundred forty-two billion, one hundred forty-three million, four hundred fifty-one thousand, five hundred fifty-one".
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