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121423425553 is a prime number
BaseRepresentation
bin111000100010101100…
…1100111000000010001
3102121102012121010021101
41301011121213000101
53442133344104203
6131440421224401
711525662042063
oct1610531470021
9377365533241
10121423425553
114754a3a3881
121b648562101
13b5b1078501
145c3c3d5733
153259e2641d
hex1c45667011

121423425553 has 2 divisors, whose sum is σ = 121423425554. Its totient is φ = 121423425552.

The previous prime is 121423425547. The next prime is 121423425569. The reversal of 121423425553 is 355524324121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118100133649 + 3323291904 = 343657^2 + 57648^2 .

It is an emirp because it is prime and its reverse (355524324121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121423425553 - 25 = 121423425521 is a prime.

It is not a weakly prime, because it can be changed into another prime (121423425503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60711712776 + 60711712777.

It is an arithmetic number, because the mean of its divisors is an integer number (60711712777).

Almost surely, 2121423425553 is an apocalyptic number.

It is an amenable number.

121423425553 is a deficient number, since it is larger than the sum of its proper divisors (1).

121423425553 is an equidigital number, since it uses as much as digits as its factorization.

121423425553 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144000, while the sum is 37.

Adding to 121423425553 its reverse (355524324121), we get a palindrome (476947749674).

The spelling of 121423425553 in words is "one hundred twenty-one billion, four hundred twenty-three million, four hundred twenty-five thousand, five hundred fifty-three".