121425331400153 has 4 divisors (see below), whose sum is σ = 132463997891088. Its totient is φ = 110386664909220.

The previous prime is 121425331400119. The next prime is 121425331400159. The reversal of 121425331400153 is 351004133524121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121425331400153 - 2⁶ = 121425331400089 is a prime.

It is a super-2 number, since 2×121425331400153² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121425331400159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5519333245451 + ... + 5519333245472.

It is an arithmetic number, because the mean of its divisors is an integer number (33115999472772).

Almost surely, 2^{121425331400153} is an apocalyptic number.

It is an amenable number.

121425331400153 is a deficient number, since it is larger than the sum of its proper divisors (11038666490935).

121425331400153 is a wasteful number, since it uses less digits than its factorization.

121425331400153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11038666490934.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 121425331400153 its reverse (351004133524121), we get a palindrome (472429464924274).

The spelling of 121425331400153 in words is "one hundred twenty-one trillion, four hundred twenty-five billion, three hundred thirty-one million, four hundred thousand, one hundred fifty-three".