Base | Representation |
---|---|
bin | 10110100111100011… |
… | …11111110011001001 |
3 | 1011100021021000111011 |
4 | 23103301333303021 |
5 | 144332104033140 |
6 | 5324535203521 |
7 | 606626040106 |
oct | 132361776311 |
9 | 34307230434 |
10 | 12143033545 |
11 | 5171475915 |
12 | 242a8165a1 |
13 | 11b6994866 |
14 | 832a11aad |
15 | 4b10c5cea |
hex | 2d3c7fcc9 |
12143033545 has 4 divisors (see below), whose sum is σ = 14571640260. Its totient is φ = 9714426832.
The previous prime is 12143033533. The next prime is 12143033557. The reversal of 12143033545 is 54533034121.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (12143033533) and next prime (12143033557).
It can be written as a sum of positive squares in 2 ways, for example, as 2395025721 + 9748007824 = 48939^2 + 98732^2 .
It is a cyclic number.
It is not a de Polignac number, because 12143033545 - 27 = 12143033417 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1214303350 + ... + 1214303359.
It is an arithmetic number, because the mean of its divisors is an integer number (3642910065).
Almost surely, 212143033545 is an apocalyptic number.
It is an amenable number.
12143033545 is a deficient number, since it is larger than the sum of its proper divisors (2428606715).
12143033545 is an equidigital number, since it uses as much as digits as its factorization.
12143033545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2428606714.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 12143033545 its reverse (54533034121), we get a palindrome (66676067666).
The spelling of 12143033545 in words is "twelve billion, one hundred forty-three million, thirty-three thousand, five hundred forty-five".
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