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1214312130103 = 2039595542977
BaseRepresentation
bin10001101010111010101…
…001001010011000110111
311022002100111111122120011
4101222322221022120313
5124343402401130403
62325503003121051
7153505533541612
oct21527251123067
94262314448504
101214312130103
11428a945a4296
12177412813187
138a680780947
1442ab7251179
15218c1426a6d
hex11abaa4a637

1214312130103 has 4 divisors (see below), whose sum is σ = 1214907675120. Its totient is φ = 1213716585088.

The previous prime is 1214312130071. The next prime is 1214312130121. The reversal of 1214312130103 is 3010312134121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1214312130103 - 25 = 1214312130071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214312130203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297769450 + ... + 297773527.

It is an arithmetic number, because the mean of its divisors is an integer number (303726918780).

Almost surely, 21214312130103 is an apocalyptic number.

1214312130103 is a deficient number, since it is larger than the sum of its proper divisors (595545017).

1214312130103 is an equidigital number, since it uses as much as digits as its factorization.

1214312130103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 595545016.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1214312130103 its reverse (3010312134121), we get a palindrome (4224624264224).

The spelling of 1214312130103 in words is "one trillion, two hundred fourteen billion, three hundred twelve million, one hundred thirty thousand, one hundred three".

Divisors: 1 2039 595542977 1214312130103