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12143122101353 is a prime number
BaseRepresentation
bin1011000010110100101001…
…1110101011010001101001
31120222212112001120011110002
42300231022132223101221
53042423103224220403
641454250121232345
72362211612550065
oct260551236532151
946885461504402
1012143122101353
1139619619459a1
1214415030326b5
136a1126047619
142dda31b18aa5
15160d0cca4188
hexb0b4a7ab469

12143122101353 has 2 divisors, whose sum is σ = 12143122101354. Its totient is φ = 12143122101352.

The previous prime is 12143122101307. The next prime is 12143122101359. The reversal of 12143122101353 is 35310122134121.

12143122101353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12123676356649 + 19445744704 = 3481907^2 + 139448^2 .

It is a cyclic number.

It is not a de Polignac number, because 12143122101353 - 224 = 12143105324137 is a prime.

It is not a weakly prime, because it can be changed into another prime (12143122101359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071561050676 + 6071561050677.

It is an arithmetic number, because the mean of its divisors is an integer number (6071561050677).

Almost surely, 212143122101353 is an apocalyptic number.

It is an amenable number.

12143122101353 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143122101353 is an equidigital number, since it uses as much as digits as its factorization.

12143122101353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 12143122101353 its reverse (35310122134121), we get a palindrome (47453244235474).

The spelling of 12143122101353 in words is "twelve trillion, one hundred forty-three billion, one hundred twenty-two million, one hundred one thousand, three hundred fifty-three".