Base | Representation |
---|---|
bin | 1011000010110100101001… |
… | …1110101011010001101010 |
3 | 1120222212112001120011110010 |
4 | 2300231022132223101222 |
5 | 3042423103224220404 |
6 | 41454250121232350 |
7 | 2362211612550066 |
oct | 260551236532152 |
9 | 46885461504403 |
10 | 12143122101354 |
11 | 39619619459a2 |
12 | 14415030326b6 |
13 | 6a112604761a |
14 | 2dda31b18aa6 |
15 | 160d0cca4189 |
hex | b0b4a7ab46a |
12143122101354 has 16 divisors (see below), whose sum is σ = 24349654766592. Its totient is φ = 4037138939808.
The previous prime is 12143122101353. The next prime is 12143122101359. The reversal of 12143122101354 is 45310122134121.
12143122101354 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (12143122101353) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2642104339 + ... + 2642108934.
It is an arithmetic number, because the mean of its divisors is an integer number (1521853422912).
Almost surely, 212143122101354 is an apocalyptic number.
12143122101354 is an abundant number, since it is smaller than the sum of its proper divisors (12206532665238).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12143122101354 is a wasteful number, since it uses less digits than its factorization.
12143122101354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5284213661.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 12143122101354 its reverse (45310122134121), we get a palindrome (57453244235475).
The spelling of 12143122101354 in words is "twelve trillion, one hundred forty-three billion, one hundred twenty-two million, one hundred one thousand, three hundred fifty-four".
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