Base | Representation |
---|---|
bin | 10110100111100100… |
… | …10101101111100111 |
3 | 1011100021102120210021 |
4 | 23103302111233213 |
5 | 144332114422211 |
6 | 5324541140011 |
7 | 606626563135 |
oct | 132362255747 |
9 | 34307376707 |
10 | 12143123431 |
11 | 51715273aa |
12 | 242a85a607 |
13 | 11b69c674a |
14 | 832a36755 |
15 | 4b10e2771 |
hex | 2d3c95be7 |
12143123431 has 2 divisors, whose sum is σ = 12143123432. Its totient is φ = 12143123430.
The previous prime is 12143123423. The next prime is 12143123437. The reversal of 12143123431 is 13432134121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12143123431 - 23 = 12143123423 is a prime.
It is a super-2 number, since 2×121431234312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12143123396 and 12143123405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12143123437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071561715 + 6071561716.
It is an arithmetic number, because the mean of its divisors is an integer number (6071561716).
Almost surely, 212143123431 is an apocalyptic number.
12143123431 is a deficient number, since it is larger than the sum of its proper divisors (1).
12143123431 is an equidigital number, since it uses as much as digits as its factorization.
12143123431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1728, while the sum is 25.
Adding to 12143123431 its reverse (13432134121), we get a palindrome (25575257552).
The spelling of 12143123431 in words is "twelve billion, one hundred forty-three million, one hundred twenty-three thousand, four hundred thirty-one".
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