121433115 has 8 divisors (see below), whose sum is σ = 194293008. Its totient is φ = 64764320.

The previous prime is 121433099. The next prime is 121433129. The reversal of 121433115 is 511334121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 121433115 - 2⁴ = 121433099 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121433091 and 121433100.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4047756 + ... + 4047785.

It is an arithmetic number, because the mean of its divisors is an integer number (24286626).

Almost surely, 2^121433115 is an apocalyptic number.

121433115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

121433115 is a deficient number, since it is larger than the sum of its proper divisors (72859893).

121433115 is an equidigital number, since it uses as much as digits as its factorization.

121433115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8095549.

The product of its digits is 360, while the sum is 21.

The square root of 121433115 is about 11019.6694596526. The cubic root of 121433115 is about 495.1981861236.

Adding to 121433115 its reverse (511334121), we get a palindrome (632767236).

The spelling of 121433115 in words is "one hundred twenty-one million, four hundred thirty-three thousand, one hundred fifteen".