12143322334121 has 4 divisors (see below), whose sum is σ = 13247260728144. Its totient is φ = 11039383940100.

The previous prime is 12143322334051. The next prime is 12143322334163.

12143322334121 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12143322334121 - 2¹⁸ = 12143322071977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12143322334321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 551969196995 + ... + 551969197016.

It is an arithmetic number, because the mean of its divisors is an integer number (3311815182036).

Almost surely, 2^{12143322334121} is an apocalyptic number.

12143322334121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12143322334121 is a deficient number, since it is larger than the sum of its proper divisors (1103938394023).

12143322334121 is a wasteful number, since it uses less digits than its factorization.

12143322334121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1103938394022.

The product of its digits is 20736, while the sum is 32.

It can be divided in two parts, 1214332 and 2334121, that added together give a palindrome (3548453).

The spelling of 12143322334121 in words is "twelve trillion, one hundred forty-three billion, three hundred twenty-two million, three hundred thirty-four thousand, one hundred twenty-one".