Base | Representation |
---|---|
bin | 10110100111100111… |
… | …10010010001111101 |
3 | 1011100022010211201102 |
4 | 23103303302101331 |
5 | 144332214034321 |
6 | 5324553222445 |
7 | 606633032156 |
oct | 132363622175 |
9 | 34308124642 |
10 | 12143502461 |
11 | 5171766152 |
12 | 242aa01a25 |
13 | 11b6aca11c |
14 | 832ad492d |
15 | 4b1169c0b |
hex | 2d3cf247d |
12143502461 has 4 divisors (see below), whose sum is σ = 12149597532. Its totient is φ = 12137407392.
The previous prime is 12143502451. The next prime is 12143502479. The reversal of 12143502461 is 16420534121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5168747236 + 6974755225 = 71894^2 + 83515^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12143502461 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12143502401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3044546 + ... + 3048531.
It is an arithmetic number, because the mean of its divisors is an integer number (3037399383).
Almost surely, 212143502461 is an apocalyptic number.
It is an amenable number.
12143502461 is a deficient number, since it is larger than the sum of its proper divisors (6095071).
12143502461 is an equidigital number, since it uses as much as digits as its factorization.
12143502461 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6095070.
The product of its (nonzero) digits is 5760, while the sum is 29.
The spelling of 12143502461 in words is "twelve billion, one hundred forty-three million, five hundred two thousand, four hundred sixty-one".
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