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1214373014473 = 1398736496507
BaseRepresentation
bin10001101010111110010…
…001011010101111001001
311022002111202001220012211
4101222332101122233021
5124344013442430343
62325513020105121
7153510203211223
oct21527621325711
94262452056184
101214373014473
114290159a9653
1217742b0951a1
138a69027a2b8
1442ac137d413
15218c695179d
hex11abe45abc9

1214373014473 has 4 divisors (see below), whose sum is σ = 1223109511120. Its totient is φ = 1205636517828.

The previous prime is 1214373014453. The next prime is 1214373014497. The reversal of 1214373014473 is 3744103734121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1214373014473 - 217 = 1214372883401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1214373014453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4368248115 + ... + 4368248392.

It is an arithmetic number, because the mean of its divisors is an integer number (305777377780).

Almost surely, 21214373014473 is an apocalyptic number.

It is an amenable number.

1214373014473 is a deficient number, since it is larger than the sum of its proper divisors (8736496647).

1214373014473 is an equidigital number, since it uses as much as digits as its factorization.

1214373014473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8736496646.

The product of its (nonzero) digits is 169344, while the sum is 40.

Adding to 1214373014473 its reverse (3744103734121), we get a palindrome (4958476748594).

The spelling of 1214373014473 in words is "one trillion, two hundred fourteen billion, three hundred seventy-three million, fourteen thousand, four hundred seventy-three".

Divisors: 1 139 8736496507 1214373014473