1214373014453 has 2 divisors, whose sum is σ = 1214373014454. Its totient is φ = 1214373014452.

The previous prime is 1214373014447. The next prime is 1214373014497. The reversal of 1214373014453 is 3544103734121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1117033382404 + 97339632049 = 1056898^2 + 311993^2 .

It is an emirp because it is prime and its reverse (3544103734121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1214373014453 - 2¹⁸ = 1214372752309 is a prime.

It is a super-2 number, since 2×1214373014453² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1214373014653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607186507226 + 607186507227.

It is an arithmetic number, because the mean of its divisors is an integer number (607186507227).

Almost surely, 2^{1214373014453} is an apocalyptic number.

It is an amenable number.

1214373014453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214373014453 is an equidigital number, since it uses as much as digits as its factorization.

1214373014453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 38.

Adding to 1214373014453 its reverse (3544103734121), we get a palindrome (4758476748574).

The spelling of 1214373014453 in words is "one trillion, two hundred fourteen billion, three hundred seventy-three million, fourteen thousand, four hundred fifty-three".