121440001104113 has 2 divisors, whose sum is σ = 121440001104114. Its totient is φ = 121440001104112.

The previous prime is 121440001104089. The next prime is 121440001104131. The reversal of 121440001104113 is 311401100044121.

Together with next prime (121440001104131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80071589682529 + 41368411421584 = 8948273^2 + 6431828^2 .

It is a cyclic number.

It is not a de Polignac number, because 121440001104113 - 2¹⁴ = 121440001087729 is a prime.

It is not a weakly prime, because it can be changed into another prime (121440001104013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60720000552056 + 60720000552057.

It is an arithmetic number, because the mean of its divisors is an integer number (60720000552057).

Almost surely, 2^{121440001104113} is an apocalyptic number.

It is an amenable number.

121440001104113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121440001104113 is an equidigital number, since it uses as much as digits as its factorization.

121440001104113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 121440001104113 its reverse (311401100044121), we get a palindrome (432841101148234).

The spelling of 121440001104113 in words is "one hundred twenty-one trillion, four hundred forty billion, one million, one hundred four thousand, one hundred thirteen".