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121441214537 is a prime number
BaseRepresentation
bin111000100011001110…
…1011110000001001001
3102121110110001220011122
41301012131132001021
53442202422331122
6131442254405025
711526266202026
oct1610635360111
9377413056148
10121441214537
1147559443a15
121b652500775
13b5b4966436
145c4090654d
15325b78c142
hex1c4675e049

121441214537 has 2 divisors, whose sum is σ = 121441214538. Its totient is φ = 121441214536.

The previous prime is 121441214533. The next prime is 121441214567. The reversal of 121441214537 is 735412144121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121441098256 + 116281 = 348484^2 + 341^2 .

It is a cyclic number.

It is not a de Polignac number, because 121441214537 - 22 = 121441214533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121441214497 and 121441214506.

It is not a weakly prime, because it can be changed into another prime (121441214533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60720607268 + 60720607269.

It is an arithmetic number, because the mean of its divisors is an integer number (60720607269).

Almost surely, 2121441214537 is an apocalyptic number.

It is an amenable number.

121441214537 is a deficient number, since it is larger than the sum of its proper divisors (1).

121441214537 is an equidigital number, since it uses as much as digits as its factorization.

121441214537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 26880, while the sum is 35.

Adding to 121441214537 its reverse (735412144121), we get a palindrome (856853358658).

The spelling of 121441214537 in words is "one hundred twenty-one billion, four hundred forty-one million, two hundred fourteen thousand, five hundred thirty-seven".