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1214413343441 is a prime number
BaseRepresentation
bin10001101011000000101…
…011010000101011010001
311022002121112221211011022
4101223000223100223101
5124344104303442231
62325521020325225
7153511203046334
oct21530053205321
94262545854138
101214413343441
11429036744381
121774406a3815
138a69872a7ac
1442ac687a61b
15218ca26ac7b
hex11ac0ad0ad1

1214413343441 has 2 divisors, whose sum is σ = 1214413343442. Its totient is φ = 1214413343440.

The previous prime is 1214413343419. The next prime is 1214413343453. The reversal of 1214413343441 is 1443433144121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1197046057216 + 17367286225 = 1094096^2 + 131785^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1214413343441 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1214413363441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607206671720 + 607206671721.

It is an arithmetic number, because the mean of its divisors is an integer number (607206671721).

Almost surely, 21214413343441 is an apocalyptic number.

It is an amenable number.

1214413343441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214413343441 is an equidigital number, since it uses as much as digits as its factorization.

1214413343441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 55296, while the sum is 35.

Adding to 1214413343441 its reverse (1443433144121), we get a palindrome (2657846487562).

The spelling of 1214413343441 in words is "one trillion, two hundred fourteen billion, four hundred thirteen million, three hundred forty-three thousand, four hundred forty-one".