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121441433 is a prime number
BaseRepresentation
bin1110011110100…
…00110010011001
322110111212022212
413033100302121
5222042111213
620014524505
73003143441
oct717206231
9273455285
10121441433
1162606823
1234806735
131c210049
14121b3121
15a9dc9a8
hex73d0c99

121441433 has 2 divisors, whose sum is σ = 121441434. Its totient is φ = 121441432.

The previous prime is 121441409. The next prime is 121441451. The reversal of 121441433 is 334144121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86062729 + 35378704 = 9277^2 + 5948^2 .

It is a cyclic number.

It is not a de Polignac number, because 121441433 - 210 = 121440409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121441399 and 121441408.

It is not a weakly prime, because it can be changed into another prime (121441493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60720716 + 60720717.

It is an arithmetic number, because the mean of its divisors is an integer number (60720717).

Almost surely, 2121441433 is an apocalyptic number.

It is an amenable number.

121441433 is a deficient number, since it is larger than the sum of its proper divisors (1).

121441433 is an equidigital number, since it uses as much as digits as its factorization.

121441433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 23.

The square root of 121441433 is about 11020.0468692288. The cubic root of 121441433 is about 495.2094926618.

Adding to 121441433 its reverse (334144121), we get a palindrome (455585554).

The spelling of 121441433 in words is "one hundred twenty-one million, four hundred forty-one thousand, four hundred thirty-three".