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1214440001041 is a prime number
BaseRepresentation
bin10001101011000010010…
…000111100111000010001
311022002200102010011111211
4101223002100330320101
5124344133120013131
62325523411540121
7153511645454311
oct21530220747021
94262612104454
101214440001041
1142904a7a1653
121774495ba641
138a6a1102317
1442aca219441
15218cc7845b1
hex11ac243ce11

1214440001041 has 2 divisors, whose sum is σ = 1214440001042. Its totient is φ = 1214440001040.

The previous prime is 1214440001017. The next prime is 1214440001053. The reversal of 1214440001041 is 1401000444121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 698722122816 + 515717878225 = 835896^2 + 718135^2 .

It is a cyclic number.

It is not a de Polignac number, because 1214440001041 - 25 = 1214440001009 is a prime.

It is a super-2 number, since 2×12144400010412 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1214440091041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607220000520 + 607220000521.

It is an arithmetic number, because the mean of its divisors is an integer number (607220000521).

Almost surely, 21214440001041 is an apocalyptic number.

It is an amenable number.

1214440001041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214440001041 is an equidigital number, since it uses as much as digits as its factorization.

1214440001041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 512, while the sum is 22.

Adding to 1214440001041 its reverse (1401000444121), we get a palindrome (2615440445162).

The spelling of 1214440001041 in words is "one trillion, two hundred fourteen billion, four hundred forty million, one thousand, forty-one".