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1214442202531 is a prime number
BaseRepresentation
bin10001101011000010011…
…001010110010110100011
311022002200120021000101111
4101223002121112112203
5124344134200440111
62325523531044151
7153512003253535
oct21530231262643
94262616230344
101214442202531
11429050a65668
1217744a2a0657
138a6a16c338c
1442aca62d855
15218cca6ba21
hex11ac26565a3

1214442202531 has 2 divisors, whose sum is σ = 1214442202532. Its totient is φ = 1214442202530.

The previous prime is 1214442202529. The next prime is 1214442202663. The reversal of 1214442202531 is 1352022444121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1214442202531 - 21 = 1214442202529 is a prime.

It is a super-2 number, since 2×12144422025312 (a number of 25 digits) contains 22 as substring.

Together with 1214442202529, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1214442202493 and 1214442202502.

It is not a weakly prime, because it can be changed into another prime (1214442203531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607221101265 + 607221101266.

It is an arithmetic number, because the mean of its divisors is an integer number (607221101266).

Almost surely, 21214442202531 is an apocalyptic number.

1214442202531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214442202531 is an equidigital number, since it uses as much as digits as its factorization.

1214442202531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 1214442202531 its reverse (1352022444121), we get a palindrome (2566464646652).

The spelling of 1214442202531 in words is "one trillion, two hundred fourteen billion, four hundred forty-two million, two hundred two thousand, five hundred thirty-one".